Base | Representation |
---|---|
bin | 111100100101010111… |
… | …1100111100000000111 |
3 | 110102211002202222020011 |
4 | 1321022233213200013 |
5 | 4112422332443211 |
6 | 135433555051051 |
7 | 12254034245614 |
oct | 1711257474007 |
9 | 412732688204 |
10 | 130103015431 |
11 | 501a3840154 |
12 | 2126b2a0a87 |
13 | c3653329cc |
14 | 642304350b |
15 | 35b6e11921 |
hex | 1e4abe7807 |
130103015431 has 2 divisors, whose sum is σ = 130103015432. Its totient is φ = 130103015430.
The previous prime is 130103015429. The next prime is 130103015437. The reversal of 130103015431 is 134510301031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130103015431 - 21 = 130103015429 is a prime.
It is a super-2 number, since 2×1301030154312 (a number of 23 digits) contains 22 as substring.
Together with 130103015429, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130103015437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051507715 + 65051507716.
It is an arithmetic number, because the mean of its divisors is an integer number (65051507716).
Almost surely, 2130103015431 is an apocalyptic number.
130103015431 is a deficient number, since it is larger than the sum of its proper divisors (1).
130103015431 is an equidigital number, since it uses as much as digits as its factorization.
130103015431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 130103015431 its reverse (134510301031), we get a palindrome (264613316462).
The spelling of 130103015431 in words is "one hundred thirty billion, one hundred three million, fifteen thousand, four hundred thirty-one".
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