Base | Representation |
---|---|
bin | 111100100101011000… |
… | …0110101001001001101 |
3 | 110102211010101010110202 |
4 | 1321022300311021031 |
5 | 4112422423132303 |
6 | 135434005543245 |
7 | 12254040042032 |
oct | 1711260651115 |
9 | 412733333422 |
10 | 130103333453 |
11 | 501a3a38085 |
12 | 2126b414b25 |
13 | c3654146a2 |
14 | 64230c7389 |
15 | 35b6e75c88 |
hex | 1e4ac3524d |
130103333453 has 2 divisors, whose sum is σ = 130103333454. Its totient is φ = 130103333452.
The previous prime is 130103333417. The next prime is 130103333461. The reversal of 130103333453 is 354333301031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 82850138569 + 47253194884 = 287837^2 + 217378^2 .
It is a cyclic number.
It is not a de Polignac number, because 130103333453 - 28 = 130103333197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130103333483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051666726 + 65051666727.
It is an arithmetic number, because the mean of its divisors is an integer number (65051666727).
Almost surely, 2130103333453 is an apocalyptic number.
It is an amenable number.
130103333453 is a deficient number, since it is larger than the sum of its proper divisors (1).
130103333453 is an equidigital number, since it uses as much as digits as its factorization.
130103333453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 29.
Adding to 130103333453 its reverse (354333301031), we get a palindrome (484436634484).
The spelling of 130103333453 in words is "one hundred thirty billion, one hundred three million, three hundred thirty-three thousand, four hundred fifty-three".
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