Base | Representation |
---|---|
bin | 10010111011101100010… |
… | …110011111110000101111 |
3 | 11121101020002112111021122 |
4 | 102323230112133300233 |
5 | 132304020113144011 |
6 | 2433405251051155 |
7 | 162666055542113 |
oct | 22735426376057 |
9 | 4541202474248 |
10 | 1301045443631 |
11 | 46185226449a |
12 | 1901995a0abb |
13 | 958c3885b3b |
14 | 46d84365743 |
15 | 23c9aad13db |
hex | 12eec59fc2f |
1301045443631 has 2 divisors, whose sum is σ = 1301045443632. Its totient is φ = 1301045443630.
The previous prime is 1301045443619. The next prime is 1301045443661. The reversal of 1301045443631 is 1363445401031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301045443631 is a prime.
It is a super-2 number, since 2×13010454436312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1301045443591 and 1301045443600.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1301045443661) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650522721815 + 650522721816.
It is an arithmetic number, because the mean of its divisors is an integer number (650522721816).
Almost surely, 21301045443631 is an apocalyptic number.
1301045443631 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301045443631 is an equidigital number, since it uses as much as digits as its factorization.
1301045443631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 35.
The spelling of 1301045443631 in words is "one trillion, three hundred one billion, forty-five million, four hundred forty-three thousand, six hundred thirty-one".
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