1301101002011 has 2 divisors, whose sum is σ = 1301101002012. Its totient is φ = 1301101002010.

The previous prime is 1301101001983. The next prime is 1301101002013. The reversal of 1301101002011 is 1102001011031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1301101002011 - 2²⁶ = 1301033893147 is a prime.

Together with 1301101002013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1301101001983 and 1301101002001.

It is not a weakly prime, because it can be changed into another prime (1301101002013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650550501005 + 650550501006.

It is an arithmetic number, because the mean of its divisors is an integer number (650550501006).

Almost surely, 2^{1301101002011} is an apocalyptic number.

1301101002011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301101002011 is an equidigital number, since it uses as much as digits as its factorization.

1301101002011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 1301101002011 its reverse (1102001011031), we get a palindrome (2403102013042).

The spelling of 1301101002011 in words is "one trillion, three hundred one billion, one hundred one million, two thousand, eleven".