Base | Representation |
---|---|
bin | 11101100101010110100100… |
… | …010100011111110010010011 |
3 | 122001200102011121212221102201 |
4 | 131211112210110133302103 |
5 | 114023211142442243402 |
6 | 1140415445022424031 |
7 | 36256103034662206 |
oct | 3545264424376223 |
9 | 561612147787381 |
10 | 130110201134227 |
11 | 38503476635476 |
12 | 1271428b132017 |
13 | 577a454645712 |
14 | 241b51dd7b93d |
15 | 10096e9171687 |
hex | 7655a451fc93 |
130110201134227 has 2 divisors, whose sum is σ = 130110201134228. Its totient is φ = 130110201134226.
The previous prime is 130110201134159. The next prime is 130110201134231. The reversal of 130110201134227 is 722431102011031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130110201134227 - 27 = 130110201134099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130110201134195 and 130110201134204.
It is not a weakly prime, because it can be changed into another prime (130110201134257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055100567113 + 65055100567114.
It is an arithmetic number, because the mean of its divisors is an integer number (65055100567114).
Almost surely, 2130110201134227 is an apocalyptic number.
130110201134227 is a deficient number, since it is larger than the sum of its proper divisors (1).
130110201134227 is an equidigital number, since it uses as much as digits as its factorization.
130110201134227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 130110201134227 its reverse (722431102011031), we get a palindrome (852541303145258).
The spelling of 130110201134227 in words is "one hundred thirty trillion, one hundred ten billion, two hundred one million, one hundred thirty-four thousand, two hundred twenty-seven".
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