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130110201134231 is a prime number
BaseRepresentation
bin11101100101010110100100…
…010100011111110010010111
3122001200102011121212221102212
4131211112210110133302113
5114023211142442243411
61140415445022424035
736256103034662213
oct3545264424376227
9561612147787385
10130110201134231
113850347663547a
121271428b13201b
13577a454645716
14241b51dd7b943
1510096e917168b
hex7655a451fc97

130110201134231 has 2 divisors, whose sum is σ = 130110201134232. Its totient is φ = 130110201134230.

The previous prime is 130110201134227. The next prime is 130110201134257. The reversal of 130110201134231 is 132431102011031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130110201134231 - 22 = 130110201134227 is a prime.

It is a super-2 number, since 2×1301102011342312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130110201134197 and 130110201134206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130110201136231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055100567115 + 65055100567116.

It is an arithmetic number, because the mean of its divisors is an integer number (65055100567116).

Almost surely, 2130110201134231 is an apocalyptic number.

130110201134231 is a deficient number, since it is larger than the sum of its proper divisors (1).

130110201134231 is an equidigital number, since it uses as much as digits as its factorization.

130110201134231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 130110201134231 its reverse (132431102011031), we get a palindrome (262541303145262).

The spelling of 130110201134231 in words is "one hundred thirty trillion, one hundred ten billion, two hundred one million, one hundred thirty-four thousand, two hundred thirty-one".