1301102142040 has 128 divisors (see below), whose sum is σ = 3201894904320. Its totient is φ = 473696870400.

The previous prime is 1301102142029. The next prime is 1301102142077. The reversal of 1301102142040 is 402412011031.

It is a super-3 number, since 3×1301102142040³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1301102141999 and 1301102142017.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 31451770 + ... + 31493110.

It is an arithmetic number, because the mean of its divisors is an integer number (25014803940).

Almost surely, 2^{1301102142040} is an apocalyptic number.

1301102142040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1301102142040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1600947452160).

1301102142040 is an abundant number, since it is smaller than the sum of its proper divisors (1900792762280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1301102142040 is a wasteful number, since it uses less digits than its factorization.

1301102142040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42893 (or 42889 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1301102142040 its reverse (402412011031), we get a palindrome (1703514153071).

The spelling of 1301102142040 in words is "one trillion, three hundred one billion, one hundred two million, one hundred forty-two thousand, forty".