Base | Representation |
---|---|
bin | 11000001111000010… |
… | …11010100110100001 |
3 | 1020120202200110200212 |
4 | 30013201122212201 |
5 | 203121320231423 |
6 | 5551025023505 |
7 | 640266354212 |
oct | 140741324641 |
9 | 36522613625 |
10 | 13011102113 |
11 | 5577478659 |
12 | 2631484b95 |
13 | 12c478b0b9 |
14 | 8b6019409 |
15 | 5123e6578 |
hex | 30785a9a1 |
13011102113 has 2 divisors, whose sum is σ = 13011102114. Its totient is φ = 13011102112.
The previous prime is 13011102107. The next prime is 13011102119. The reversal of 13011102113 is 31120111031.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (13011102107) and next prime (13011102119).
It can be written as a sum of positive squares in only one way, i.e., 9465733264 + 3545368849 = 97292^2 + 59543^2 .
It is a cyclic number.
It is not a de Polignac number, because 13011102113 - 224 = 12994324897 is a prime.
It is not a weakly prime, because it can be changed into another prime (13011102119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505551056 + 6505551057.
It is an arithmetic number, because the mean of its divisors is an integer number (6505551057).
Almost surely, 213011102113 is an apocalyptic number.
It is an amenable number.
13011102113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011102113 is an equidigital number, since it uses as much as digits as its factorization.
13011102113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 13011102113 its reverse (31120111031), we get a palindrome (44131213144).
The spelling of 13011102113 in words is "thirteen billion, eleven million, one hundred two thousand, one hundred thirteen".
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