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130112020444561 is a prime number
BaseRepresentation
bin11101100101011000010000…
…110000100111010110010001
3122001200120212102020111000221
4131211120100300213112101
5114023223404213211221
61140420345332513041
736256166105604031
oct3545302060472621
9561616772214027
10130112020444561
113850421a589231
12127146b847b781
13577a684536ccc
14241b65383d8c1
1510097a3c41541
hex765610c27591

130112020444561 has 2 divisors, whose sum is σ = 130112020444562. Its totient is φ = 130112020444560.

The previous prime is 130112020444537. The next prime is 130112020444591. The reversal of 130112020444561 is 165444020211031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127081092650625 + 3030927793936 = 11273025^2 + 1740956^2 .

It is a cyclic number.

It is not a de Polignac number, because 130112020444561 - 225 = 130111986890129 is a prime.

It is not a weakly prime, because it can be changed into another prime (130112020444591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056010222280 + 65056010222281.

It is an arithmetic number, because the mean of its divisors is an integer number (65056010222281).

Almost surely, 2130112020444561 is an apocalyptic number.

It is an amenable number.

130112020444561 is a deficient number, since it is larger than the sum of its proper divisors (1).

130112020444561 is an equidigital number, since it uses as much as digits as its factorization.

130112020444561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 130112020444561 its reverse (165444020211031), we get a palindrome (295556040655592).

The spelling of 130112020444561 in words is "one hundred thirty trillion, one hundred twelve billion, twenty million, four hundred forty-four thousand, five hundred sixty-one".