Base | Representation |
---|---|
bin | 11101100101011000010000… |
… | …110000100111010110010001 |
3 | 122001200120212102020111000221 |
4 | 131211120100300213112101 |
5 | 114023223404213211221 |
6 | 1140420345332513041 |
7 | 36256166105604031 |
oct | 3545302060472621 |
9 | 561616772214027 |
10 | 130112020444561 |
11 | 3850421a589231 |
12 | 127146b847b781 |
13 | 577a684536ccc |
14 | 241b65383d8c1 |
15 | 10097a3c41541 |
hex | 765610c27591 |
130112020444561 has 2 divisors, whose sum is σ = 130112020444562. Its totient is φ = 130112020444560.
The previous prime is 130112020444537. The next prime is 130112020444591. The reversal of 130112020444561 is 165444020211031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127081092650625 + 3030927793936 = 11273025^2 + 1740956^2 .
It is a cyclic number.
It is not a de Polignac number, because 130112020444561 - 225 = 130111986890129 is a prime.
It is not a weakly prime, because it can be changed into another prime (130112020444591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056010222280 + 65056010222281.
It is an arithmetic number, because the mean of its divisors is an integer number (65056010222281).
Almost surely, 2130112020444561 is an apocalyptic number.
It is an amenable number.
130112020444561 is a deficient number, since it is larger than the sum of its proper divisors (1).
130112020444561 is an equidigital number, since it uses as much as digits as its factorization.
130112020444561 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 34.
Adding to 130112020444561 its reverse (165444020211031), we get a palindrome (295556040655592).
The spelling of 130112020444561 in words is "one hundred thirty trillion, one hundred twelve billion, twenty million, four hundred forty-four thousand, five hundred sixty-one".
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