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1301120303209 is a prime number
BaseRepresentation
bin10010111011110000110…
…100000100000001101001
311121101102022101202022121
4102323300310010001221
5132304143244200314
62433420523351241
7163000655045446
oct22736064040151
94541368352277
101301120303209
11461890544611
121901ba682521
139590623654c
1446d902909cd
1523ca246bd24
hex12ef0d04069

1301120303209 has 2 divisors, whose sum is σ = 1301120303210. Its totient is φ = 1301120303208.

The previous prime is 1301120303167. The next prime is 1301120303227. The reversal of 1301120303209 is 9023030211031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1194273037584 + 106847265625 = 1092828^2 + 326875^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301120303209 - 29 = 1301120302697 is a prime.

It is not a weakly prime, because it can be changed into another prime (1301120303269) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650560151604 + 650560151605.

It is an arithmetic number, because the mean of its divisors is an integer number (650560151605).

Almost surely, 21301120303209 is an apocalyptic number.

It is an amenable number.

1301120303209 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301120303209 is an equidigital number, since it uses as much as digits as its factorization.

1301120303209 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

The spelling of 1301120303209 in words is "one trillion, three hundred one billion, one hundred twenty million, three hundred three thousand, two hundred nine".