130112110220032 has 72 divisors (see below), whose sum is σ = 260288339415552. Its totient is φ = 64912722969600.

The previous prime is 130112110220009. The next prime is 130112110220047. The reversal of 130112110220032 is 230022011211031.

It is a super-2 number, since 2×130112110220032² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130112110219991 and 130112110220009.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 869013657 + ... + 869163367.

It is an arithmetic number, because the mean of its divisors is an integer number (3615115825216).

Almost surely, 2^{130112110220032} is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130112110220032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (130144169707776).

130112110220032 is an abundant number, since it is smaller than the sum of its proper divisors (130176229195520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130112110220032 is an equidigital number, since it uses as much as digits as its factorization.

130112110220032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157185 (or 157171 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 130112110220032 its reverse (230022011211031), we get a palindrome (360134121431063).

Subtracting 130112110220032 from its reverse (230022011211031), we obtain a palindrome (99909900990999).

The spelling of 130112110220032 in words is "one hundred thirty trillion, one hundred twelve billion, one hundred ten million, two hundred twenty thousand, thirty-two".