130112113 has 2 divisors, whose sum is σ = 130112114. Its totient is φ = 130112112.

The previous prime is 130112111. The next prime is 130112117. The reversal of 130112113 is 311211031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88792929 + 41319184 = 9423^2 + 6428^2 .

It is an emirp because it is prime and its reverse (311211031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130112113 - 2¹ = 130112111 is a prime.

Together with 130112111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 130112093 and 130112102.

It is not a weakly prime, because it can be changed into another prime (130112111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056056 + 65056057.

It is an arithmetic number, because the mean of its divisors is an integer number (65056057).

Almost surely, 2^130112113 is an apocalyptic number.

It is an amenable number.

130112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

130112113 is an equidigital number, since it uses as much as digits as its factorization.

130112113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 130112113 is about 11406.6696717315. The cubic root of 130112113 is about 506.7252861443.

Adding to 130112113 its reverse (311211031), we get a palindrome (441323144).

The spelling of 130112113 in words is "one hundred thirty million, one hundred twelve thousand, one hundred thirteen".