130112111 has 2 divisors, whose sum is σ = 130112112. Its totient is φ = 130112110.

The previous prime is 130112083. The next prime is 130112113. The reversal of 130112111 is 111211031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130112111 is a prime.

It is a super-2 number, since 2×130112111² = 33858322857752642, which contains 22 as substring.

Together with 130112113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130112092 and 130112101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130112113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056055 + 65056056.

It is an arithmetic number, because the mean of its divisors is an integer number (65056056).

Almost surely, 2^130112111 is an apocalyptic number.

130112111 is a deficient number, since it is larger than the sum of its proper divisors (1).

130112111 is an equidigital number, since it uses as much as digits as its factorization.

130112111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

The square root of 130112111 is about 11406.6695840635. The cubic root of 130112111 is about 506.7252835480.

Adding to 130112111 its reverse (111211031), we get a palindrome (241323142).

The spelling of 130112111 in words is "one hundred thirty million, one hundred twelve thousand, one hundred eleven".