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130112320439 is a prime number
BaseRepresentation
bin111100100101101001…
…1000111001110110111
3110102211202021201022002
41321023103013032313
54112432223223224
6135434530325515
712254206322123
oct1711323071667
9412752251262
10130112320439
11501a9016142
122127242989b
13c36724012a
146424386583
1535b7b4d9ae
hex1e4b4c73b7

130112320439 has 2 divisors, whose sum is σ = 130112320440. Its totient is φ = 130112320438.

The previous prime is 130112320411. The next prime is 130112320441. The reversal of 130112320439 is 934023211031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130112320439 is a prime.

Together with 130112320441, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130112320409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056160219 + 65056160220.

It is an arithmetic number, because the mean of its divisors is an integer number (65056160220).

Almost surely, 2130112320439 is an apocalyptic number.

130112320439 is a deficient number, since it is larger than the sum of its proper divisors (1).

130112320439 is an equidigital number, since it uses as much as digits as its factorization.

130112320439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 29.

The spelling of 130112320439 in words is "one hundred thirty billion, one hundred twelve million, three hundred twenty thousand, four hundred thirty-nine".