Base | Representation |
---|---|
bin | 1011110101010110111010… |
… | …1101011000101110101111 |
3 | 1201001212110210112022000011 |
4 | 2331111232231120232233 |
5 | 3201134132203043434 |
6 | 43401152000314051 |
7 | 2512015321336135 |
oct | 275255655305657 |
9 | 51055423468004 |
10 | 13011313331119 |
11 | 4167081197924 |
12 | 156181a612927 |
13 | 734c6679a69c |
14 | 32da72779755 |
15 | 1786c29b9e64 |
hex | bd56eb58baf |
13011313331119 has 2 divisors, whose sum is σ = 13011313331120. Its totient is φ = 13011313331118.
The previous prime is 13011313331101. The next prime is 13011313331147. The reversal of 13011313331119 is 91113331311031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13011313331119 - 219 = 13011312806831 is a prime.
It is a super-2 number, since 2×130113133311192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13011113331119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505656665559 + 6505656665560.
It is an arithmetic number, because the mean of its divisors is an integer number (6505656665560).
Almost surely, 213011313331119 is an apocalyptic number.
13011313331119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011313331119 is an equidigital number, since it uses as much as digits as its factorization.
13011313331119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2187, while the sum is 31.
The spelling of 13011313331119 in words is "thirteen trillion, eleven billion, three hundred thirteen million, three hundred thirty-one thousand, one hundred nineteen".
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