Base | Representation |
---|---|
bin | 1011110101010110111111… |
… | …0100101110001101000100 |
3 | 1201001212112002201100211110 |
4 | 2331111233310232031010 |
5 | 3201134202000000200 |
6 | 43401153505205020 |
7 | 2512015636312461 |
oct | 275255764561504 |
9 | 51055462640743 |
10 | 13011332031300 |
11 | 41670907aa619 |
12 | 1561824930770 |
13 | 734c6a617295 |
14 | 32da75046668 |
15 | 1786c4460b50 |
hex | bd56fd2e344 |
13011332031300 has 72 divisors (see below), whose sum is σ = 37650781688800. Its totient is φ = 3469258955520.
The previous prime is 13011332031277. The next prime is 13011332031311. The reversal of 13011332031300 is 313023311031.
It is a super-2 number, since 2×130113320313002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 254170 + ... + 5107569.
Almost surely, 213011332031300 is an apocalyptic number.
13011332031300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13011332031300 is an abundant number, since it is smaller than the sum of its proper divisors (24639449657500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13011332031300 is a wasteful number, since it uses less digits than its factorization.
13011332031300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5369845 (or 5369838 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 13011332031300 its reverse (313023311031), we get a palindrome (13324355342331).
The spelling of 13011332031300 in words is "thirteen trillion, eleven billion, three hundred thirty-two million, thirty-one thousand, three hundred".
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