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130114305222 = 23111971428867
BaseRepresentation
bin111100100101101101…
…0101011110011000110
3110102211220000112220120
41321023122223303012
54112433230231342
6135435041042410
712254232226506
oct1711332536306
9412756015816
10130114305222
11501aa151360
1221273026406
13c367786665
146424741a06
1535b7de1aec
hex1e4b6abcc6

130114305222 has 16 divisors (see below), whose sum is σ = 283885756992. Its totient is φ = 39428577320.

The previous prime is 130114305197. The next prime is 130114305227. The reversal of 130114305222 is 222503411031.

130114305222 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 130114305192 and 130114305201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130114305227) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 985714368 + ... + 985714499.

It is an arithmetic number, because the mean of its divisors is an integer number (17742859812).

Almost surely, 2130114305222 is an apocalyptic number.

130114305222 is an abundant number, since it is smaller than the sum of its proper divisors (153771451770).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130114305222 is a wasteful number, since it uses less digits than its factorization.

130114305222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1971428883.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 130114305222 its reverse (222503411031), we get a palindrome (352617716253).

The spelling of 130114305222 in words is "one hundred thirty billion, one hundred fourteen million, three hundred five thousand, two hundred twenty-two".

Divisors: 1 2 3 6 11 22 33 66 1971428867 3942857734 5914286601 11828573202 21685717537 43371435074 65057152611 130114305222