130120404021031 has 2 divisors, whose sum is σ = 130120404021032. Its totient is φ = 130120404021030.

The previous prime is 130120404020989. The next prime is 130120404021073.

130120404021031 is nontrivially palindromic in base 10.

It is a balanced prime because it is at equal distance from previous prime (130120404020989) and next prime (130120404021073).

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 130120404021031 - 2²¹ = 130120401923879 is a prime.

It is a super-2 number, since 2×130120404021031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130120404020993 and 130120404021011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130120404031031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65060202010515 + 65060202010516.

It is an arithmetic number, because the mean of its divisors is an integer number (65060202010516).

Almost surely, 2^{130120404021031} is an apocalyptic number.

130120404021031 is a deficient number, since it is larger than the sum of its proper divisors (1).

130120404021031 is an equidigital number, since it uses as much as digits as its factorization.

130120404021031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

It can be divided in two parts, 13012040 and 4021031, that added together give a palindrome (17033071).

The spelling of 130120404021031 in words is "one hundred thirty trillion, one hundred twenty billion, four hundred four million, twenty-one thousand, thirty-one".