Base | Representation |
---|---|
bin | 1011110101011010000010… |
… | …1010111001110000000100 |
3 | 1201001221122012202202102221 |
4 | 2331112200222321300010 |
5 | 3201142341243300430 |
6 | 43401411102142124 |
7 | 2512045150113022 |
oct | 275264052716004 |
9 | 51057565682387 |
10 | 13012151540740 |
11 | 4167471356150 |
12 | 1561a13281944 |
13 | 73506b33b201 |
14 | 32db11c0d712 |
15 | 17872138d57a |
hex | bd5a0ab9c04 |
13012151540740 has 24 divisors (see below), whose sum is σ = 29809656257472. Its totient is φ = 4731691469280.
The previous prime is 13012151540723. The next prime is 13012151540777. The reversal of 13012151540740 is 4704515121031.
It is a junction number, because it is equal to n+sod(n) for n = 13012151540696 and 13012151540705.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29573071464 + ... + 29573071903.
It is an arithmetic number, because the mean of its divisors is an integer number (1242069010728).
Almost surely, 213012151540740 is an apocalyptic number.
13012151540740 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13012151540740 is an abundant number, since it is smaller than the sum of its proper divisors (16797504716732).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13012151540740 is a wasteful number, since it uses less digits than its factorization.
13012151540740 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59146143387 (or 59146143385 counting only the distinct ones).
The product of its (nonzero) digits is 16800, while the sum is 34.
Adding to 13012151540740 its reverse (4704515121031), we get a palindrome (17716666661771).
The spelling of 13012151540740 in words is "thirteen trillion, twelve billion, one hundred fifty-one million, five hundred forty thousand, seven hundred forty".
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