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130122110117 is a prime number
BaseRepresentation
bin111100100101111100…
…0011101010010100101
3110102212102201002012202
41321023320131102211
54112442230010432
6135435520224245
712254355454346
oct1711370352245
9412772632182
10130122110117
11502035a228a
122127576b085
13c36928a03c
1464257b40cd
1535b8934462
hex1e4be1d4a5

130122110117 has 2 divisors, whose sum is σ = 130122110118. Its totient is φ = 130122110116.

The previous prime is 130122110101. The next prime is 130122110137. The reversal of 130122110117 is 711011221031.

It is an a-pointer prime, because the next prime (130122110137) can be obtained adding 130122110117 to its sum of digits (20).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106084398436 + 24037711681 = 325706^2 + 155041^2 .

It is an emirp because it is prime and its reverse (711011221031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130122110117 - 24 = 130122110101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130122110137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65061055058 + 65061055059.

It is an arithmetic number, because the mean of its divisors is an integer number (65061055059).

Almost surely, 2130122110117 is an apocalyptic number.

It is an amenable number.

130122110117 is a deficient number, since it is larger than the sum of its proper divisors (1).

130122110117 is an equidigital number, since it uses as much as digits as its factorization.

130122110117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 20.

Adding to 130122110117 its reverse (711011221031), we get a palindrome (841133331148).

The spelling of 130122110117 in words is "one hundred thirty billion, one hundred twenty-two million, one hundred ten thousand, one hundred seventeen".