Base | Representation |
---|---|
bin | 1011110101011010010011… |
… | …1000100001101001100111 |
3 | 1201001221211010202200101202 |
4 | 2331112210320201221213 |
5 | 3201143012342032103 |
6 | 43401422105113115 |
7 | 2512046665641443 |
oct | 275264470415147 |
9 | 51057733680352 |
10 | 13012222220903 |
11 | 41674a8241204 |
12 | 1561a32a8879b |
13 | 73507cb874a9 |
14 | 32db1b36b823 |
15 | 1787276a0988 |
hex | bd5a4e21a67 |
13012222220903 has 2 divisors, whose sum is σ = 13012222220904. Its totient is φ = 13012222220902.
The previous prime is 13012222220897. The next prime is 13012222220909. The reversal of 13012222220903 is 30902222221031.
It is a balanced prime because it is at equal distance from previous prime (13012222220897) and next prime (13012222220909).
It is a cyclic number.
It is not a de Polignac number, because 13012222220903 - 218 = 13012221958759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13012222220909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506111110451 + 6506111110452.
It is an arithmetic number, because the mean of its divisors is an integer number (6506111110452).
Almost surely, 213012222220903 is an apocalyptic number.
13012222220903 is a deficient number, since it is larger than the sum of its proper divisors (1).
13012222220903 is an equidigital number, since it uses as much as digits as its factorization.
13012222220903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13012222220903 its reverse (30902222221031), we get a palindrome (43914444441934).
The spelling of 13012222220903 in words is "thirteen trillion, twelve billion, two hundred twenty-two million, two hundred twenty thousand, nine hundred three".
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