Base | Representation |
---|---|
bin | 1011110101011010010110… |
… | …0001101110001011100010 |
3 | 1201001221211220002100011010 |
4 | 2331112211201232023202 |
5 | 3201143023123121010 |
6 | 43401423132401350 |
7 | 2512050156510201 |
oct | 275264541561342 |
9 | 51057756070133 |
10 | 13012233020130 |
11 | 4167503347893 |
12 | 1561a36616256 |
13 | 735082198a76 |
14 | 32db1c97d238 |
15 | 1787285d5620 |
hex | bd5a586e2e2 |
13012233020130 has 32 divisors (see below), whose sum is σ = 31229496897984. Its totient is φ = 3469913510976.
The previous prime is 13012233020119. The next prime is 13012233020167. The reversal of 13012233020130 is 3102033221031.
It is a junction number, because it is equal to n+sod(n) for n = 13012233020097 and 13012233020106.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7067949 + ... + 8716671.
It is an arithmetic number, because the mean of its divisors is an integer number (975921778062).
Almost surely, 213012233020130 is an apocalyptic number.
13012233020130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13012233020130 is an abundant number, since it is smaller than the sum of its proper divisors (18217263877854).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13012233020130 is a wasteful number, since it uses less digits than its factorization.
13012233020130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1911810.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13012233020130 its reverse (3102033221031), we get a palindrome (16114266241161).
The spelling of 13012233020130 in words is "thirteen trillion, twelve billion, two hundred thirty-three million, twenty thousand, one hundred thirty".
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