Base | Representation |
---|---|
bin | 10010111011110111010… |
… | …110101100000011001100 |
3 | 11121101200221220010110220 |
4 | 102323313112230003030 |
5 | 132304404342341330 |
6 | 2433435443431340 |
7 | 163003456605513 |
oct | 22736726540314 |
9 | 4541627803426 |
10 | 1301230043340 |
11 | 461937488a37 |
12 | 19022b385550 |
13 | 95922baa536 |
14 | 46da0a9967a |
15 | 23cabde7710 |
hex | 12ef75ac0cc |
1301230043340 has 48 divisors (see below), whose sum is σ = 3662519777280. Its totient is φ = 345177949120.
The previous prime is 1301230043329. The next prime is 1301230043353. The reversal of 1301230043340 is 433400321031.
It is a self number, because there is not a number n which added to its sum of digits gives 1301230043340.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56761230 + ... + 56784149.
It is an arithmetic number, because the mean of its divisors is an integer number (76302495360).
Almost surely, 21301230043340 is an apocalyptic number.
1301230043340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1301230043340 is an abundant number, since it is smaller than the sum of its proper divisors (2361289733940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1301230043340 is a wasteful number, since it uses less digits than its factorization.
1301230043340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113545582 (or 113545580 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 1301230043340 its reverse (433400321031), we get a palindrome (1734630364371).
The spelling of 1301230043340 in words is "one trillion, three hundred one billion, two hundred thirty million, forty-three thousand, three hundred forty".
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