Base | Representation |
---|---|
bin | 11101100101100010110001… |
… | …101010111001111101011100 |
3 | 122001201200000012120001021111 |
4 | 131211202301222321331130 |
5 | 114023420014330424200 |
6 | 1140425453503311404 |
7 | 36260045632425361 |
oct | 3545426152717534 |
9 | 561650005501244 |
10 | 130123310014300 |
11 | 38508a93217059 |
12 | 127169292ab564 |
13 | 577b763449aa5 |
14 | 241c004d6a468 |
15 | 1009c14e2e0ba |
hex | 7658b1ab9f5c |
130123310014300 has 36 divisors (see below), whose sum is σ = 282411355264696. Its totient is φ = 52041255336000.
The previous prime is 130123310014223. The next prime is 130123310014307. The reversal of 130123310014300 is 3410013321031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130123310014307) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 100210047 + ... + 101500246.
Almost surely, 2130123310014300 is an apocalyptic number.
130123310014300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130123310014300 is an abundant number, since it is smaller than the sum of its proper divisors (152288045250396).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130123310014300 is a wasteful number, since it uses less digits than its factorization.
130123310014300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 201716758 (or 201716751 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 130123310014300 its reverse (3410013321031), we get a palindrome (133533323335331).
The spelling of 130123310014300 in words is "one hundred thirty trillion, one hundred twenty-three billion, three hundred ten million, fourteen thousand, three hundred".
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