130124230113130 has 64 divisors (see below), whose sum is σ = 266657403138048. Its totient is φ = 45255286359360.

The previous prime is 130124230113079. The next prime is 130124230113133. The reversal of 130124230113130 is 31311032421031.

It is a junction number, because it is equal to n+sod(n) for n = 130124230113095 and 130124230113104.

It is not an unprimeable number, because it can be changed into a prime (130124230113133) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18557449 + ... + 24589171.

It is an arithmetic number, because the mean of its divisors is an integer number (4166521924032).

Almost surely, 2^{130124230113130} is an apocalyptic number.

130124230113130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130124230113130 is an abundant number, since it is smaller than the sum of its proper divisors (136533173024918).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130124230113130 is a wasteful number, since it uses less digits than its factorization.

130124230113130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6040291.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 130124230113130 its reverse (31311032421031), we get a palindrome (161435262534161).

The spelling of 130124230113130 in words is "one hundred thirty trillion, one hundred twenty-four billion, two hundred thirty million, one hundred thirteen thousand, one hundred thirty".