Base | Representation |
---|---|
bin | 1011110101011011001100… |
… | …1000010100001100111111 |
3 | 1201001222102210112011112112 |
4 | 2331112303020110030333 |
5 | 3201144010034204101 |
6 | 43401501524124235 |
7 | 2512055630403461 |
oct | 275266310241477 |
9 | 51058383464475 |
10 | 13012461241151 |
11 | 41676101556a9 |
12 | 1561a9ab3667b |
13 | 7350ba5543a8 |
14 | 32db40dca131 |
15 | 17873d6666bb |
hex | bd5b321433f |
13012461241151 has 2 divisors, whose sum is σ = 13012461241152. Its totient is φ = 13012461241150.
The previous prime is 13012461241123. The next prime is 13012461241187. The reversal of 13012461241151 is 15114216421031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13012461241151 - 222 = 13012457046847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13012461241111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506230620575 + 6506230620576.
It is an arithmetic number, because the mean of its divisors is an integer number (6506230620576).
Almost surely, 213012461241151 is an apocalyptic number.
13012461241151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13012461241151 is an equidigital number, since it uses as much as digits as its factorization.
13012461241151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 32.
Adding to 13012461241151 its reverse (15114216421031), we get a palindrome (28126677662182).
The spelling of 13012461241151 in words is "thirteen trillion, twelve billion, four hundred sixty-one million, two hundred forty-one thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •