Base | Representation |
---|---|
bin | 10010111011111011110… |
… | …000111011011100100001 |
3 | 11121101220010010002110221 |
4 | 102323323300323130201 |
5 | 132310032312443014 |
6 | 2433451045323041 |
7 | 163005345521143 |
oct | 22737360733441 |
9 | 4541803102427 |
10 | 1301304031009 |
11 | 461975222a74 |
12 | 190250106481 |
13 | 95935314118 |
14 | 46daa838c93 |
15 | 23cb365eb24 |
hex | 12efbc3b721 |
1301304031009 has 2 divisors, whose sum is σ = 1301304031010. Its totient is φ = 1301304031008.
The previous prime is 1301304030989. The next prime is 1301304031033. The reversal of 1301304031009 is 9001304031031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1278871480384 + 22432550625 = 1130872^2 + 149775^2 .
It is a cyclic number.
It is not a de Polignac number, because 1301304031009 - 223 = 1301295642401 is a prime.
It is a super-2 number, since 2×13013040310092 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1301304331009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650652015504 + 650652015505.
It is an arithmetic number, because the mean of its divisors is an integer number (650652015505).
Almost surely, 21301304031009 is an apocalyptic number.
It is an amenable number.
1301304031009 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301304031009 is an equidigital number, since it uses as much as digits as its factorization.
1301304031009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 1301304031009 in words is "one trillion, three hundred one billion, three hundred four million, thirty-one thousand, nine".
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