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1301312232133 is a prime number
BaseRepresentation
bin10010111011111100010…
…000001101101011000101
311121101220200112202022021
4102323330100031223011
5132310041412412013
62433451541203141
7163005505316134
oct22737420155305
94541820482267
101301312232133
11461979914661
12190252a004b1
1395936c25c64
1446dab97191b
1523cb422ea8d
hex12efc40dac5

1301312232133 has 2 divisors, whose sum is σ = 1301312232134. Its totient is φ = 1301312232132.

The previous prime is 1301312232067. The next prime is 1301312232151. The reversal of 1301312232133 is 3312322131031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 865973552929 + 435338679204 = 930577^2 + 659802^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1301312232133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1301312232098 and 1301312232107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301312232163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650656116066 + 650656116067.

It is an arithmetic number, because the mean of its divisors is an integer number (650656116067).

Almost surely, 21301312232133 is an apocalyptic number.

It is an amenable number.

1301312232133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301312232133 is an equidigital number, since it uses as much as digits as its factorization.

1301312232133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1301312232133 its reverse (3312322131031), we get a palindrome (4613634363164).

The spelling of 1301312232133 in words is "one trillion, three hundred one billion, three hundred twelve million, two hundred thirty-two thousand, one hundred thirty-three".