Base | Representation |
---|---|
bin | 11101100101101010111000… |
… | …010110010110111100011100 |
3 | 122001202111110122212212202222 |
4 | 131211222320112112330130 |
5 | 114024040330033044400 |
6 | 1140433453201204512 |
7 | 36260504366212202 |
oct | 3545527026267434 |
9 | 561674418785688 |
10 | 130132012003100 |
11 | 38511749272038 |
12 | 12718557630738 |
13 | 577c51c2475a3 |
14 | 241c5cc969072 |
15 | 100a073d91185 |
hex | 765ab8596f1c |
130132012003100 has 36 divisors (see below), whose sum is σ = 282472797073488. Its totient is φ = 52036891248000.
The previous prime is 130132012003051. The next prime is 130132012003117. The reversal of 130132012003100 is 1300210231031.
It is a super-2 number, since 2×1301320120031002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 198590681 + ... + 199244880.
Almost surely, 2130132012003100 is an apocalyptic number.
130132012003100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130132012003100 is an abundant number, since it is smaller than the sum of its proper divisors (152340785070388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130132012003100 is a wasteful number, since it uses less digits than its factorization.
130132012003100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 397838846 (or 397838839 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 130132012003100 its reverse (1300210231031), we get a palindrome (131432222234131).
The spelling of 130132012003100 in words is "one hundred thirty trillion, one hundred thirty-two billion, twelve million, three thousand, one hundred".
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