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1301320998353 is a prime number
BaseRepresentation
bin10010111011111100110…
…001101001110111010001
311121101221022001010022002
4102323330301221313101
5132310101133421403
62433452453123345
7163005642656465
oct22737461516721
94541838033262
101301320998353
11461983861872
12190255929555
13959389a507c
1446dacbb44a5
1523cb4db2188
hex12efcc69dd1

1301320998353 has 2 divisors, whose sum is σ = 1301320998354. Its totient is φ = 1301320998352.

The previous prime is 1301320998337. The next prime is 1301320998377. The reversal of 1301320998353 is 3538990231031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 848476792384 + 452844205969 = 921128^2 + 672937^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301320998353 - 24 = 1301320998337 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1301320998298 and 1301320998307.

It is not a weakly prime, because it can be changed into another prime (1301320998553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650660499176 + 650660499177.

It is an arithmetic number, because the mean of its divisors is an integer number (650660499177).

Almost surely, 21301320998353 is an apocalyptic number.

It is an amenable number.

1301320998353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301320998353 is an equidigital number, since it uses as much as digits as its factorization.

1301320998353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 524880, while the sum is 47.

The spelling of 1301320998353 in words is "one trillion, three hundred one billion, three hundred twenty million, nine hundred ninety-eight thousand, three hundred fifty-three".