Base | Representation |
---|---|
bin | 11101100101101010111111… |
… | …011000111100100101000011 |
3 | 122001202111202220010221111221 |
4 | 131211222333120330211003 |
5 | 114024041100302401201 |
6 | 1140433513021015511 |
7 | 36260510332210261 |
oct | 3545527730744503 |
9 | 561674686127457 |
10 | 130132130122051 |
11 | 385117a9a09602 |
12 | 1271858b0b4597 |
13 | 577c53a863265 |
14 | 241c600515431 |
15 | 100a07e4244a1 |
hex | 765abf63c943 |
130132130122051 has 2 divisors, whose sum is σ = 130132130122052. Its totient is φ = 130132130122050.
The previous prime is 130132130122039. The next prime is 130132130122063. The reversal of 130132130122051 is 150221031231031.
It is a balanced prime because it is at equal distance from previous prime (130132130122039) and next prime (130132130122063).
It is a cyclic number.
It is not a de Polignac number, because 130132130122051 - 27 = 130132130121923 is a prime.
It is not a weakly prime, because it can be changed into another prime (130132130122091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066065061025 + 65066065061026.
It is an arithmetic number, because the mean of its divisors is an integer number (65066065061026).
Almost surely, 2130132130122051 is an apocalyptic number.
130132130122051 is a deficient number, since it is larger than the sum of its proper divisors (1).
130132130122051 is an equidigital number, since it uses as much as digits as its factorization.
130132130122051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 130132130122051 its reverse (150221031231031), we get a palindrome (280353161353082).
The spelling of 130132130122051 in words is "one hundred thirty trillion, one hundred thirty-two billion, one hundred thirty million, one hundred twenty-two thousand, fifty-one".
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