Base | Representation |
---|---|
bin | 1011110101011110000100… |
… | …0110001101100010100111 |
3 | 1201002001102112200012112211 |
4 | 2331113201012031202213 |
5 | 3201202100001112021 |
6 | 43402110233424251 |
7 | 2512114013451151 |
oct | 275274106154247 |
9 | 51061375605484 |
10 | 13013232441511 |
11 | 4167976505975 |
12 | 156207526b087 |
13 | 7351b1262773 |
14 | 32dbb55b9ad1 |
15 | 1787862003e1 |
hex | bd5e118d8a7 |
13013232441511 has 2 divisors, whose sum is σ = 13013232441512. Its totient is φ = 13013232441510.
The previous prime is 13013232441401. The next prime is 13013232441589. The reversal of 13013232441511 is 11514423231031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13013232441511 - 213 = 13013232433319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13013232441211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506616220755 + 6506616220756.
It is an arithmetic number, because the mean of its divisors is an integer number (6506616220756).
Almost surely, 213013232441511 is an apocalyptic number.
13013232441511 is a deficient number, since it is larger than the sum of its proper divisors (1).
13013232441511 is an equidigital number, since it uses as much as digits as its factorization.
13013232441511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 13013232441511 its reverse (11514423231031), we get a palindrome (24527655672542).
The spelling of 13013232441511 in words is "thirteen trillion, thirteen billion, two hundred thirty-two million, four hundred forty-one thousand, five hundred eleven".
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