Base | Representation |
---|---|
bin | 111100100110010000… |
… | …1110011011011000111 |
3 | 110102220012002201220222 |
4 | 1321030201303123013 |
5 | 4113003013324204 |
6 | 135440544414555 |
7 | 12254546545556 |
oct | 1711441633307 |
9 | 412805081828 |
10 | 130132948679 |
11 | 50209725478 |
12 | 2127931745b |
13 | c36b5b34a6 |
14 | 6426dd5d9d |
15 | 35b9875abe |
hex | 1e4c8736c7 |
130132948679 has 2 divisors, whose sum is σ = 130132948680. Its totient is φ = 130132948678.
The previous prime is 130132948619. The next prime is 130132948691. The reversal of 130132948679 is 976849231031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130132948679 - 228 = 129864513223 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130132948679.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130132948619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066474339 + 65066474340.
It is an arithmetic number, because the mean of its divisors is an integer number (65066474340).
Almost surely, 2130132948679 is an apocalyptic number.
130132948679 is a deficient number, since it is larger than the sum of its proper divisors (1).
130132948679 is an equidigital number, since it uses as much as digits as its factorization.
130132948679 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 53.
It can be divided in two parts, 13013 and 2948679, that added together give a palindrome (2961692).
The spelling of 130132948679 in words is "one hundred thirty billion, one hundred thirty-two million, nine hundred forty-eight thousand, six hundred seventy-nine".
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