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130134030505421 is a prime number
BaseRepresentation
bin11101100101101100110000…
…101010010101010111001101
3122001202200200100001102102012
4131211230300222111113031
5114024103443302133141
61140434425344511005
736260605406204465
oct3545546052252715
9561680610042365
10130134030505421
11385125946a6778
1212718a1b61b465
13577c78149c467
14241c740a7cba5
15100a1411aaceb
hex765b30a955cd

130134030505421 has 2 divisors, whose sum is σ = 130134030505422. Its totient is φ = 130134030505420.

The previous prime is 130134030505379. The next prime is 130134030505439. The reversal of 130134030505421 is 124505030431031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129166384489321 + 967646016100 = 11365139^2 + 983690^2 .

It is an emirp because it is prime and its reverse (124505030431031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130134030505421 - 26 = 130134030505357 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130134030505481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65067015252710 + 65067015252711.

It is an arithmetic number, because the mean of its divisors is an integer number (65067015252711).

Almost surely, 2130134030505421 is an apocalyptic number.

It is an amenable number.

130134030505421 is a deficient number, since it is larger than the sum of its proper divisors (1).

130134030505421 is an equidigital number, since it uses as much as digits as its factorization.

130134030505421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 130134030505421 its reverse (124505030431031), we get a palindrome (254639060936452).

The spelling of 130134030505421 in words is "one hundred thirty trillion, one hundred thirty-four billion, thirty million, five hundred five thousand, four hundred twenty-one".