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13014177973 is a prime number
BaseRepresentation
bin11000001111011010…
…01001100010110101
31020120222110201222121
430013231021202311
5203123112143343
65551214555541
7640334454556
oct140755114265
936528421877
1013014177973
115579189595
122632508bb1
1312c52c7134
148b65ba32d
15512802aed
hex307b498b5

13014177973 has 2 divisors, whose sum is σ = 13014177974. Its totient is φ = 13014177972.

The previous prime is 13014177971. The next prime is 13014177989. The reversal of 13014177973 is 37977141031.

13014177973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12936332644 + 77845329 = 113738^2 + 8823^2 .

It is a cyclic number.

It is not a de Polignac number, because 13014177973 - 21 = 13014177971 is a prime.

Together with 13014177971, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13014177971) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507088986 + 6507088987.

It is an arithmetic number, because the mean of its divisors is an integer number (6507088987).

Almost surely, 213014177973 is an apocalyptic number.

It is an amenable number.

13014177973 is a deficient number, since it is larger than the sum of its proper divisors (1).

13014177973 is an equidigital number, since it uses as much as digits as its factorization.

13014177973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 111132, while the sum is 43.

The spelling of 13014177973 in words is "thirteen billion, fourteen million, one hundred seventy-seven thousand, nine hundred seventy-three".