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1301450230807 is a prime number
BaseRepresentation
bin10010111100000100011…
…110101000110000010111
311121102021022012210220021
4102330010132220300113
5132310332224341212
62433513351050011
7163012102302466
oct22740436506027
94542238183807
101301450230807
11461a3a7aa051
12190291070907
13959596b238c
1446dc20149dd
1523cc13dd307
hex12f047a8c17

1301450230807 has 2 divisors, whose sum is σ = 1301450230808. Its totient is φ = 1301450230806.

The previous prime is 1301450230781. The next prime is 1301450230823. The reversal of 1301450230807 is 7080320541031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1301450230807 - 235 = 1267090492439 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301450233807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650725115403 + 650725115404.

It is an arithmetic number, because the mean of its divisors is an integer number (650725115404).

Almost surely, 21301450230807 is an apocalyptic number.

1301450230807 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301450230807 is an equidigital number, since it uses as much as digits as its factorization.

1301450230807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 1301450230807 its reverse (7080320541031), we get a palindrome (8381770771838).

The spelling of 1301450230807 in words is "one trillion, three hundred one billion, four hundred fifty million, two hundred thirty thousand, eight hundred seven".