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1301450461 is a prime number
BaseRepresentation
bin100110110010010…
…1000111011011101
310100200220112101221
41031210220323131
510131132403321
6333050333341
744152101133
oct11544507335
93320815357
101301450461
116086a8aa3
12303a2a251
1317982523c
14c4bbb753
15793c9e41
hex4d928edd

1301450461 has 2 divisors, whose sum is σ = 1301450462. Its totient is φ = 1301450460.

The previous prime is 1301450443. The next prime is 1301450473. The reversal of 1301450461 is 1640541031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1030024836 + 271425625 = 32094^2 + 16475^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301450461 - 213 = 1301442269 is a prime.

It is a super-2 number, since 2×13014504612 = 3387546604874225042, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301450431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650725230 + 650725231.

It is an arithmetic number, because the mean of its divisors is an integer number (650725231).

Almost surely, 21301450461 is an apocalyptic number.

It is an amenable number.

1301450461 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301450461 is an equidigital number, since it uses as much as digits as its factorization.

1301450461 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 1301450461 is about 36075.6214222292. The cubic root of 1301450461 is about 1091.7986354791.

Adding to 1301450461 its reverse (1640541031), we get a palindrome (2941991492).

The spelling of 1301450461 in words is "one billion, three hundred one million, four hundred fifty thousand, four hundred sixty-one".