Base | Representation |
---|---|
bin | 1111100000111… |
… | …10010000010111 |
3 | 100001220011121021 |
4 | 13300132100113 |
5 | 231304203401 |
6 | 20525302011 |
7 | 3140143225 |
oct | 760362027 |
9 | 301804537 |
10 | 130147351 |
11 | 675126a4 |
12 | 37704907 |
13 | 20c6a889 |
14 | 133dbb15 |
15 | b65c2a1 |
hex | 7c1e417 |
130147351 has 2 divisors, whose sum is σ = 130147352. Its totient is φ = 130147350.
The previous prime is 130147337. The next prime is 130147361. The reversal of 130147351 is 153741031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130147351 - 29 = 130146839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130147301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65073675 + 65073676.
It is an arithmetic number, because the mean of its divisors is an integer number (65073676).
Almost surely, 2130147351 is an apocalyptic number.
130147351 is a deficient number, since it is larger than the sum of its proper divisors (1).
130147351 is an equidigital number, since it uses as much as digits as its factorization.
130147351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 25.
The square root of 130147351 is about 11408.2141897845. The cubic root of 130147351 is about 506.7710271429.
Adding to 130147351 its reverse (153741031), we get a palindrome (283888382).
The spelling of 130147351 in words is "one hundred thirty million, one hundred forty-seven thousand, three hundred fifty-one".
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