1301503441421 has 2 divisors, whose sum is σ = 1301503441422. Its totient is φ = 1301503441420.

The previous prime is 1301503441379. The next prime is 1301503441423. The reversal of 1301503441421 is 1241443051031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1170107341225 + 131396100196 = 1081715^2 + 362486^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301503441421 - 2²² = 1301499247117 is a prime.

It is a super-2 number, since 2×1301503441421² (a number of 25 digits) contains 22 as substring.

Together with 1301503441423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301503441423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650751720710 + 650751720711.

It is an arithmetic number, because the mean of its divisors is an integer number (650751720711).

Almost surely, 2^{1301503441421} is an apocalyptic number.

It is an amenable number.

1301503441421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301503441421 is an equidigital number, since it uses as much as digits as its factorization.

1301503441421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 1301503441421 its reverse (1241443051031), we get a palindrome (2542946492452).

The spelling of 1301503441421 in words is "one trillion, three hundred one billion, five hundred three million, four hundred forty-one thousand, four hundred twenty-one".