Base | Representation |
---|---|
bin | 11000001111100010… |
… | …01101000110110111 |
3 | 1020121001110202101021 |
4 | 30013301031012313 |
5 | 203123400204033 |
6 | 5551253442011 |
7 | 640346503312 |
oct | 140761150667 |
9 | 36531422337 |
10 | 13015241143 |
11 | 5579845343 |
12 | 2632940307 |
13 | 12c55aa028 |
14 | 8b67b5979 |
15 | 512962b2d |
hex | 307c4d1b7 |
13015241143 has 2 divisors, whose sum is σ = 13015241144. Its totient is φ = 13015241142.
The previous prime is 13015241137. The next prime is 13015241171. The reversal of 13015241143 is 34114251031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13015241143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13015241443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507620571 + 6507620572.
It is an arithmetic number, because the mean of its divisors is an integer number (6507620572).
Almost surely, 213015241143 is an apocalyptic number.
13015241143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13015241143 is an equidigital number, since it uses as much as digits as its factorization.
13015241143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13015241143 its reverse (34114251031), we get a palindrome (47129492174).
The spelling of 13015241143 in words is "thirteen billion, fifteen million, two hundred forty-one thousand, one hundred forty-three".
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