Base | Representation |
---|---|
bin | 11101100101111111111100… |
… | …100100110101101000110111 |
3 | 122001211122212001102200001011 |
4 | 131211333330210311220313 |
5 | 114024423141130023012 |
6 | 1140452113503213051 |
7 | 36262235046513412 |
oct | 3545777444655067 |
9 | 561748761380034 |
10 | 130154631486007 |
11 | 385202a6393367 |
12 | 12720a0a8a7187 |
13 | 57816b55270bb |
14 | 241d736ac4b79 |
15 | 100a949a8a1a7 |
hex | 765ffc935a37 |
130154631486007 has 2 divisors, whose sum is σ = 130154631486008. Its totient is φ = 130154631486006.
The previous prime is 130154631485911. The next prime is 130154631486023. The reversal of 130154631486007 is 700684136451031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130154631486007 is a prime.
It is a super-3 number, since 3×1301546314860073 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130154631483007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65077315743003 + 65077315743004.
It is an arithmetic number, because the mean of its divisors is an integer number (65077315743004).
Almost surely, 2130154631486007 is an apocalyptic number.
130154631486007 is a deficient number, since it is larger than the sum of its proper divisors (1).
130154631486007 is an equidigital number, since it uses as much as digits as its factorization.
130154631486007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 49.
The spelling of 130154631486007 in words is "one hundred thirty trillion, one hundred fifty-four billion, six hundred thirty-one million, four hundred eighty-six thousand, seven".
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