Base | Representation |
---|---|
bin | 11101100110001010111101… |
… | …111011101111001010000010 |
3 | 122001212210101210002002221211 |
4 | 131212022331323233022002 |
5 | 114030121410122113200 |
6 | 1140501352041440334 |
7 | 36263134233401344 |
oct | 3546127573571202 |
9 | 561783353062854 |
10 | 130166465426050 |
11 | 385253193336a9 |
12 | 12723171aa00aa |
13 | 5782850158aa1 |
14 | 242013a637294 |
15 | 100addd957aba |
hex | 7662bdeef282 |
130166465426050 has 24 divisors (see below), whose sum is σ = 249919613620992. Its totient is φ = 50387018874000.
The previous prime is 130166465426047. The next prime is 130166465426161. The reversal of 130166465426050 is 50624564661031.
It is a super-3 number, since 3×1301664654260503 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 130166465425985 and 130166465426003.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 41989180846 + ... + 41989183945.
It is an arithmetic number, because the mean of its divisors is an integer number (10413317234208).
Almost surely, 2130166465426050 is an apocalyptic number.
130166465426050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130166465426050 is a deficient number, since it is larger than the sum of its proper divisors (119753148194942).
130166465426050 is a wasteful number, since it uses less digits than its factorization.
130166465426050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83978364834 (or 83978364829 counting only the distinct ones).
The product of its (nonzero) digits is 3110400, while the sum is 49.
The spelling of 130166465426050 in words is "one hundred thirty trillion, one hundred sixty-six billion, four hundred sixty-five million, four hundred twenty-six thousand, fifty".
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