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130200112151 is a prime number
BaseRepresentation
bin111100101000010001…
…0000000110000010111
3110110001212110222212222
41321100202000300113
54113122212042101
6135451344132555
712256323456464
oct1712042006027
9413055428788
10130200112151
115024362937a
122129790715b
13c37c49aba5
146431cba66b
1535c06e101b
hex1e50880c17

130200112151 has 2 divisors, whose sum is σ = 130200112152. Its totient is φ = 130200112150.

The previous prime is 130200112129. The next prime is 130200112153. The reversal of 130200112151 is 151211002031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130200112151 is a prime.

Together with 130200112153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130200112153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65100056075 + 65100056076.

It is an arithmetic number, because the mean of its divisors is an integer number (65100056076).

Almost surely, 2130200112151 is an apocalyptic number.

130200112151 is a deficient number, since it is larger than the sum of its proper divisors (1).

130200112151 is an equidigital number, since it uses as much as digits as its factorization.

130200112151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 130200112151 its reverse (151211002031), we get a palindrome (281411114182).

The spelling of 130200112151 in words is "one hundred thirty billion, two hundred million, one hundred twelve thousand, one hundred fifty-one".