Base | Representation |
---|---|
bin | 10010111100100110000… |
… | …001100011001100000101 |
3 | 11121110201112020000212021 |
4 | 102330212001203030011 |
5 | 132313010313444143 |
6 | 2434045253523141 |
7 | 163032045106051 |
oct | 22744601431405 |
9 | 4543645200767 |
10 | 1302013031173 |
11 | 4621a945a318 |
12 | 1904096434b1 |
13 | 95a19184c4a |
14 | 47036a76c61 |
15 | 23d05a0dced |
hex | 12f26063305 |
1302013031173 has 2 divisors, whose sum is σ = 1302013031174. Its totient is φ = 1302013031172.
The previous prime is 1302013031167. The next prime is 1302013031281. The reversal of 1302013031173 is 3711303102031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1291548150369 + 10464880804 = 1136463^2 + 102298^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302013031173 is a prime.
It is a super-3 number, since 3×13020130311733 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1302013038173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651006515586 + 651006515587.
It is an arithmetic number, because the mean of its divisors is an integer number (651006515587).
Almost surely, 21302013031173 is an apocalyptic number.
It is an amenable number.
1302013031173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302013031173 is an equidigital number, since it uses as much as digits as its factorization.
1302013031173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
The spelling of 1302013031173 in words is "one trillion, three hundred two billion, thirteen million, thirty-one thousand, one hundred seventy-three".
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