Base | Representation |
---|---|
bin | 1011110101111000001001… |
… | …0000000011110101111100 |
3 | 1201002201111021221000201102 |
4 | 2331132002100003311330 |
5 | 3201310413131403200 |
6 | 43405224523432232 |
7 | 2512452315324263 |
oct | 275360220036574 |
9 | 51081437830642 |
10 | 13020231122300 |
11 | 416a938039386 |
12 | 15634a9085678 |
13 | 735a581c60bc |
14 | 33027acb15da |
15 | 178a458586d5 |
hex | bd782403d7c |
13020231122300 has 72 divisors (see below), whose sum is σ = 28488309964800. Its totient is φ = 5164917912000.
The previous prime is 13020231122209. The next prime is 13020231122309. The reversal of 13020231122300 is 322113202031.
13020231122300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13020231122309) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 30253625 + ... + 30680975.
Almost surely, 213020231122300 is an apocalyptic number.
13020231122300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13020231122300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14244154982400).
13020231122300 is an abundant number, since it is smaller than the sum of its proper divisors (15468078842500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13020231122300 is a wasteful number, since it uses less digits than its factorization.
13020231122300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 429891 (or 429884 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13020231122300 its reverse (322113202031), we get a palindrome (13342344324331).
The spelling of 13020231122300 in words is "thirteen trillion, twenty billion, two hundred thirty-one million, one hundred twenty-two thousand, three hundred".
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