Base | Representation |
---|---|
bin | 11101100110101101010010… |
… | …000110111100101010100111 |
3 | 122002000022111121202212111221 |
4 | 131212231102012330222213 |
5 | 114031222340122200203 |
6 | 1140530324141041211 |
7 | 36265610266621504 |
oct | 3546552206745247 |
9 | 562008447685457 |
10 | 130203311131303 |
11 | 38539a06816383 |
12 | 1272a335556207 |
13 | 5786172883147 |
14 | 2421c33d164ab |
15 | 100bd4856dabd |
hex | 766b521bcaa7 |
130203311131303 has 2 divisors, whose sum is σ = 130203311131304. Its totient is φ = 130203311131302.
The previous prime is 130203311131291. The next prime is 130203311131321. The reversal of 130203311131303 is 303131113302031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130203311131303 - 221 = 130203309034151 is a prime.
It is a super-3 number, since 3×1302033111313033 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130203311131343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65101655565651 + 65101655565652.
It is an arithmetic number, because the mean of its divisors is an integer number (65101655565652).
Almost surely, 2130203311131303 is an apocalyptic number.
130203311131303 is a deficient number, since it is larger than the sum of its proper divisors (1).
130203311131303 is an equidigital number, since it uses as much as digits as its factorization.
130203311131303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 130203311131303 its reverse (303131113302031), we get a palindrome (433334424433334).
The spelling of 130203311131303 in words is "one hundred thirty trillion, two hundred three billion, three hundred eleven million, one hundred thirty-one thousand, three hundred three".
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