Base | Representation |
---|---|
bin | 111100101000010111… |
… | …0100111011000110001 |
3 | 110110002002200212001221 |
4 | 1321100232213120301 |
5 | 4113124033303423 |
6 | 135451543025041 |
7 | 12256363530151 |
oct | 1712056473061 |
9 | 413062625057 |
10 | 130203416113 |
11 | 50245485721 |
12 | 21298a3b181 |
13 | c3800869b4 |
14 | 64324da761 |
15 | 35c0b44e5d |
hex | 1e50ba7631 |
130203416113 has 2 divisors, whose sum is σ = 130203416114. Its totient is φ = 130203416112.
The previous prime is 130203416111. The next prime is 130203416149. The reversal of 130203416113 is 311614302031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 124264710144 + 5938705969 = 352512^2 + 77063^2 .
It is a cyclic number.
It is not a de Polignac number, because 130203416113 - 21 = 130203416111 is a prime.
Together with 130203416111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (130203416111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65101708056 + 65101708057.
It is an arithmetic number, because the mean of its divisors is an integer number (65101708057).
Almost surely, 2130203416113 is an apocalyptic number.
It is an amenable number.
130203416113 is a deficient number, since it is larger than the sum of its proper divisors (1).
130203416113 is an equidigital number, since it uses as much as digits as its factorization.
130203416113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 130203416113 its reverse (311614302031), we get a palindrome (441817718144).
The spelling of 130203416113 in words is "one hundred thirty billion, two hundred three million, four hundred sixteen thousand, one hundred thirteen".
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