Base | Representation |
---|---|
bin | 111100101000010111… |
… | …0100111011001011001 |
3 | 110110002002200212010102 |
4 | 1321100232213121121 |
5 | 4113124033304103 |
6 | 135451543025145 |
7 | 12256363530236 |
oct | 1712056473131 |
9 | 413062625112 |
10 | 130203416153 |
11 | 50245485758 |
12 | 21298a3b1b5 |
13 | c380086a15 |
14 | 64324da78d |
15 | 35c0b44e88 |
hex | 1e50ba7659 |
130203416153 has 2 divisors, whose sum is σ = 130203416154. Its totient is φ = 130203416152.
The previous prime is 130203416149. The next prime is 130203416179. The reversal of 130203416153 is 351614302031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67344402064 + 62859014089 = 259508^2 + 250717^2 .
It is a cyclic number.
It is not a de Polignac number, because 130203416153 - 22 = 130203416149 is a prime.
It is a super-2 number, since 2×1302034161532 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130203416113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65101708076 + 65101708077.
It is an arithmetic number, because the mean of its divisors is an integer number (65101708077).
Almost surely, 2130203416153 is an apocalyptic number.
It is an amenable number.
130203416153 is a deficient number, since it is larger than the sum of its proper divisors (1).
130203416153 is an equidigital number, since it uses as much as digits as its factorization.
130203416153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 130203416153 its reverse (351614302031), we get a palindrome (481817718184).
The spelling of 130203416153 in words is "one hundred thirty billion, two hundred three million, four hundred sixteen thousand, one hundred fifty-three".
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