Base | Representation |
---|---|
bin | 1011110101111011110101… |
… | …0100011101001010000111 |
3 | 1201002211001100200110010211 |
4 | 2331132331110131022013 |
5 | 3201314430331132221 |
6 | 43405511124300251 |
7 | 2512516010624413 |
oct | 275367524351207 |
9 | 51084040613124 |
10 | 13021222130311 |
11 | 41702a648036a |
12 | 1563724b41687 |
13 | 735b85605485 |
14 | 33033275bd43 |
15 | 178aa28606e1 |
hex | bd7bd51d287 |
13021222130311 has 2 divisors, whose sum is σ = 13021222130312. Its totient is φ = 13021222130310.
The previous prime is 13021222130309. The next prime is 13021222130341. The reversal of 13021222130311 is 11303122212031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13021222130311 - 21 = 13021222130309 is a prime.
It is a super-3 number, since 3×130212221303113 (a number of 40 digits) contains 333 as substring.
Together with 13021222130309, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13021222130341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510611065155 + 6510611065156.
It is an arithmetic number, because the mean of its divisors is an integer number (6510611065156).
Almost surely, 213021222130311 is an apocalyptic number.
13021222130311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13021222130311 is an equidigital number, since it uses as much as digits as its factorization.
13021222130311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 13021222130311 its reverse (11303122212031), we get a palindrome (24324344342342).
The spelling of 13021222130311 in words is "thirteen trillion, twenty-one billion, two hundred twenty-two million, one hundred thirty thousand, three hundred eleven".
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