Base | Representation |
---|---|
bin | 11101100110110101101010… |
… | …011111010011010001001000 |
3 | 122002001011201202221000010010 |
4 | 131212311222133103101020 |
5 | 114031344302341244422 |
6 | 1140534413124151520 |
7 | 36266346300621066 |
oct | 3546655237232110 |
9 | 562034652830103 |
10 | 130212310103112 |
11 | 38542804475066 |
12 | 127300272385a0 |
13 | 5786c78063433 |
14 | 2422449141036 |
15 | 100c1c35e5b0c |
hex | 766d6a7d3448 |
130212310103112 has 64 divisors (see below), whose sum is σ = 336769505236800. Its totient is φ = 41905726311680.
The previous prime is 130212310103107. The next prime is 130212310103123. The reversal of 130212310103112 is 211301013212031.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13633738 + ... + 21125894.
It is an arithmetic number, because the mean of its divisors is an integer number (5262023519325).
Almost surely, 2130212310103112 is an apocalyptic number.
130212310103112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
130212310103112 is an abundant number, since it is smaller than the sum of its proper divisors (206557195133688).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130212310103112 is a wasteful number, since it uses less digits than its factorization.
130212310103112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7517166 (or 7517162 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 130212310103112 its reverse (211301013212031), we get a palindrome (341513323315143).
The spelling of 130212310103112 in words is "one hundred thirty trillion, two hundred twelve billion, three hundred ten million, one hundred three thousand, one hundred twelve".
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